Asked by Shyra

A survey is being planned to determine the mean amount of time corporation executives watch television. A pilot survey indicated that the mean time per week is 12 hours, with a standard deviation of 3 hours. It is desired to estimate the mean viewing time within one quarter hour. The 0.95 degree of confidence is to be used. How many executives should be surveyed?

Is the following soluntion correct?
[(1.96*3)/0.25]^2 = 553.1 => 554
Answered by matt
YES!
Answered by Visha


A survey is being planned to determine the mean amount of time corporation executives watch television. A pilot survey indicated that the mean time per week is 14 hours, with a standard deviation of 2.5 hours. It is desired to estimate the mean viewing time within one-quarter hour. The 95 percent level of confidence is to be used.
How many executives should be surveyed?
Answered by Jeannine
Population mean = 14

Population standard deviation = 2.5

Margin error = 1/4 = 0.25

level of confidence = 0.95

z = 1.96

n =[(1.96*3)/0.25]^2
=553.19
=554
Answered by Shawn
Statistical Techniques in Business and Economics 15 edition three years after this post STILL has all the answers wrong for this section.
19. Correct answer is 97
21 correct answer is 196
23 correct answer is 554
25. E=.04,Z=1.96,p=.6, find N.
N=576.24=577(round up)
Answered by Ryan
Because Shawn, you guys are doing the problems wrong
Answered by rizwan
(1.96*2.5)/0.25)^2=384.16

that's right or wrong??
i'm not understand why the population standard deviation round up to 3??
anyone help? this for question post by shyra..
Answered by jie
A survey is being planned to determine the mean amount of time corporation executives watch television. A pilot survey indicated that the mean time per week is 13 hours, with a standard deviation of 2.0 hours. It is desired to estimate the mean viewing time within one-quarter hour. The 90% level of confidence is to be used.
Answered by Agatamudi
Here Population mean = 13, S.D = 2
Maximum error = 1/4 = 0.25
Level of significance = 90%
therefore zalfa/2 value = 1.645
n = (Zalfa/2*sigma/E)2 = (1.645*2/0.25)2=1082.41
Answered by ahmeyer
The U.S. Dairy Industry wants to estimate the mean yearly milk consumption. A sample of 16 people reveals the mean yearly consumption to be 60 gallons with a standard deviation of 20 gallons.
Answered by Srt
xbar ± t*s/vn

= 60 ± 1.75*20/4
= ( 51.25, 68.75)
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