Asked by john
The cabin noise level of the new Airbus 380 is 5 decibels lower than that of a 747 Jumbo Jet. By what factor does the noise intensity decrease?
Answers
Answered by
Henry
db = 10log(p2/p1) = -5.
The negative sign means p2 is less than p1 and the ratio is less yhan 1.
10log(p2/p1) = -5,
Divide both sides by 10:
log(p2/p1) = -0.5,
p2/p1 = 10^-0.5 = 0.316.
The negative sign means p2 is less than p1 and the ratio is less yhan 1.
10log(p2/p1) = -5,
Divide both sides by 10:
log(p2/p1) = -0.5,
p2/p1 = 10^-0.5 = 0.316.
Answered by
Ali
db = 10log(p2/p1) = 5.
10log(p2/p1) = 5,
Divide both sides by 10:
log(p2/p1) = 0.5,
p2/p1 = 10^0.5 = 3.16.
10log(p2/p1) = 5,
Divide both sides by 10:
log(p2/p1) = 0.5,
p2/p1 = 10^0.5 = 3.16.
There are no AI answers yet. The ability to request AI answers is coming soon!