Question
Find two consecutive even intergers such that the square of the smaller is 10 more than the larger.
Answers
first number --- x
next consecutive even number --- x+2
x^2= x+2 + 10
x^2 - x - 12 = 0
(x-4)(x+3) = 0
x = 4 or x = -3 , but x has to be even
x = 4
numbers are 4 and 6
check: square of smaller is 16
10 more than the larger is 10+6 = 16
Yeah!
next consecutive even number --- x+2
x^2= x+2 + 10
x^2 - x - 12 = 0
(x-4)(x+3) = 0
x = 4 or x = -3 , but x has to be even
x = 4
numbers are 4 and 6
check: square of smaller is 16
10 more than the larger is 10+6 = 16
Yeah!
Related Questions
the sum of three intergers is 193.The smaller two are consecutive intergers and the larger two are c...
the larger of two consecutive integers is 7 greater than twice the smaller. find the intergers
Here's the problem. I have to write an equationa and solve.
The greater of two consecutive intege...
Find 2 consecutive positive intergers such of the first and the square of the second is 19