Asked by royce calvin

A 200-kg crate is moved across a frictionless floor by applying a net force of 70 N for 5 seconds. This results in a final speed of 3 m/s after the crate moves a distance of 5m. What is the final kinetic energy of the crate?
Answered by Carey
KE=(mv^2)/2 = (200*3^2)/2 = 900J
Answered by Kaku
The above is corect
Answered by Kaku
The above is correct.
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