Asked by PHYSICS
Charlie now moved onto the next hole where he hit the ball with an initial speed of 30 m s-1 and at an angle of 60 degrees. This time the ball lands with a speed of 17.3 m s-1. Use g = 9.8 m s-2.
Answers
Answered by
Henry
What is the question?.
Vo = 30m/s[60o].
Xo = 30*Cos60 = 15 m/s.
Yo = 30*sin60 = 25.0 m/s.
Range = Vo^2*sin(2A)/g.
A = 60o.
Y^2 = Yo^2 + 2g*h.
Y = 0, Yo = 25 m/s, g = -9.8 m/s^2, h = ?.
Vo = 30m/s[60o].
Xo = 30*Cos60 = 15 m/s.
Yo = 30*sin60 = 25.0 m/s.
Range = Vo^2*sin(2A)/g.
A = 60o.
Y^2 = Yo^2 + 2g*h.
Y = 0, Yo = 25 m/s, g = -9.8 m/s^2, h = ?.
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