prove identity cscx-(cosx)(cotx)=sinx

1 answer

LS = 1/sinx - cosx(cosx/sinx)
= (1 - cos^2x)/sinx
= sin^2x/sinx
= sinx
= RS
Similar Questions
  1. My previous question:Verify that (secx/sinx)*(cotx/cscx)=cscx is an identity. (secx/sinx)*(cotx/cscx) = (secx/cscx)(cotx/sinx) =
    1. answers icon 2 answers
  2. Verify the identity .(cscX-cotX)^2=1-cosX/1+cosX _______ sorry i cant help you (cscX-cotX)=1/sinX - cosX/sinX = (1-cosX)/sinX If
    1. answers icon 0 answers
  3. Prove the identitycscx+cotx-1/cotx-cscx+1 = 1+cosx/sinx
    1. answers icon 3 answers
  4. express this in sinx(1/ cscx + cotx )+ (1/cscx- cotx) i got 2sinx is that right?? and B) express in cosx problem: is 1 +
    1. answers icon 1 answer
more similar questions