Asked by Katie
Suppose you roll a bowling ball at 2.5 m/s across the roof of a flat building. It leaves the edge and strikes the ground 2.0 s later.
How high is the roof?
How far from the edge of the roof does the ball hit the ground?
How high is the roof?
How far from the edge of the roof does the ball hit the ground?
Answers
Answered by
drwls
Height = (1/2) g t^2
Distance from edge = 2.5 m/s * 2.0 s.
Distance from edge = 2.5 m/s * 2.0 s.
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