Asked by lorah hilpolep
Calculate the energy of a photon of electromagnetic radiation at each of the following frequencies.
(A) 103.1 MHz (typical frequency for FM radio broadcasting)
(B) 1015 kHz (typical frequency for AM radio broadcasting) (assume four significant figures)
835.6 MHz (common frequency used for cell phone communication)
For part A i got these (in J)but they are wrong: 1.93×10^−32, 6.83×10^−25, 6.83×10^−24, 6.83×10^−23
For part B i got this, but it is wrong too: 6.96×10^−26
(A) 103.1 MHz (typical frequency for FM radio broadcasting)
(B) 1015 kHz (typical frequency for AM radio broadcasting) (assume four significant figures)
835.6 MHz (common frequency used for cell phone communication)
For part A i got these (in J)but they are wrong: 1.93×10^−32, 6.83×10^−25, 6.83×10^−24, 6.83×10^−23
For part B i got this, but it is wrong too: 6.96×10^−26
Answers
Answered by
bobpursley
E=hf=plancksconstant*103.1E6
=6.626E-34 J s*103.1E6 which does not agree with your answer. Redo them.
How do you possibly list four answers for a)?
=6.626E-34 J s*103.1E6 which does not agree with your answer. Redo them.
How do you possibly list four answers for a)?
Answered by
Dale
6.725x10^-28
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