Asked by nikko
Calculate the energy of a photon emitted when an electron in a hydrogen atom undergoes a transition from ๐=4 to ๐=1.
energy emitted: ______ J
energy emitted: ______ J
Answers
Answered by
DrBob222
delta E = 2.18E-18 (1/(n1)2 - 1/(n2)2
delta E = 2.18E-18 (1/1^2 - 1/4^2) Joules = 2.18E-18 (1/1 - 1/16) Joules
Post your work if you get stuck.
delta E = 2.18E-18 (1/1^2 - 1/4^2) Joules = 2.18E-18 (1/1 - 1/16) Joules
Post your work if you get stuck.
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