Asked by don
A woman who weighs 4.33 X10^2 N is leaning against a smooth vertical wall, as the drawing shows.
The height of the wall from her shoulder to her hand is .400m
the angle at which she is laying on the wall is 50 degrees and the rest of the height at which she is leaning against the wall is 1.10 m im trying my best to explain this picture.
(a) Find the force FN (directed perpendicular to the wall) exerted on her shoulder by the wall.
(b) Find the horizontal component of the force exerted on her shoes by the ground.
(c) Find the vertical component of the force exerted on her shoes by the ground.
The height of the wall from her shoulder to her hand is .400m
the angle at which she is laying on the wall is 50 degrees and the rest of the height at which she is leaning against the wall is 1.10 m im trying my best to explain this picture.
(a) Find the force FN (directed perpendicular to the wall) exerted on her shoulder by the wall.
(b) Find the horizontal component of the force exerted on her shoes by the ground.
(c) Find the vertical component of the force exerted on her shoes by the ground.
Answers
Answered by
bobpursley
the angle is 50 degrees.... <measured how>
the rest of the height is ...<I have no idea what this means>
the rest of the height is ...<I have no idea what this means>
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.