Asked by Ashley
A woman who weighs 500N stands on an 8.0-m-long board that weighs 100N. The board is supported at each end. The support force at the right end is 3 times the support force at the left end. How far from the right end is the woman standing?
Answers
Answered by
drwls
Let the left end support force be F1 and the right end support force = F2
3F1 = F2 (You are told this)
F1 + F2 = (4/3)F2 = 600 N (From vertical force balance)
F2 = 450 N ; F1 = 150 N
Let the woman's distance from left end = x.
Apply a moment balance. You can apply it anywhere, but chose the left end.
500 x +100*4 = F2*8 = 3600
Complete the solution for x. It will be in meters
3F1 = F2 (You are told this)
F1 + F2 = (4/3)F2 = 600 N (From vertical force balance)
F2 = 450 N ; F1 = 150 N
Let the woman's distance from left end = x.
Apply a moment balance. You can apply it anywhere, but chose the left end.
500 x +100*4 = F2*8 = 3600
Complete the solution for x. It will be in meters
Answered by
Lili
1.6
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