Asked by Ashley
                A woman who weighs 500N stands on an 8.0-m-long board that weighs 100N. The board is supported at each end. The support force at the right end is 3 times the support force at the left end. How far from the right end is the woman standing?
            
            
        Answers
                    Answered by
            drwls
            
    Let the left end support force be F1  and the right end support force = F2
3F1 = F2 (You are told this)
F1 + F2 = (4/3)F2 = 600 N (From vertical force balance)
F2 = 450 N ; F1 = 150 N
Let the woman's distance from left end = x.
Apply a moment balance. You can apply it anywhere, but chose the left end.
500 x +100*4 = F2*8 = 3600
Complete the solution for x. It will be in meters
    
3F1 = F2 (You are told this)
F1 + F2 = (4/3)F2 = 600 N (From vertical force balance)
F2 = 450 N ; F1 = 150 N
Let the woman's distance from left end = x.
Apply a moment balance. You can apply it anywhere, but chose the left end.
500 x +100*4 = F2*8 = 3600
Complete the solution for x. It will be in meters
                    Answered by
            Lili
            
    1.6
    
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.