Asked by JAZZY

A rectangle has length & width in the ratio of 3:2.If the length is increased by 8 & width is increased by 50%.The ratio of new perimeter to original perimeter is 8:5.Find the area of new rectangle
Answered by Reiny
let the length be 3x and
let the width be 2x

new length = 3x + 8
new width = 1.5(2x) = 3x

original perimeter = 2(3x) + 2(2x) = 10x
new perimeter = 2(3x+8)+ 2(3x)
= 12x + 16

(12x+16)/(10x) = 8/5
80x = 60x + 80
20x = 80
x = 40
so new length = 3(40)+8 = 128
new width = 3(40) = 120
new area = 128x120 = 15360

use the suitable units, you gave none.
Answered by Reiny
"20x = 80
x = 40 "

How silly of me ! , that should have been

x = 4
so new rectangle is 20 by 12 for an area of 240
Answered by brelan
5yd 6yd u
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