Question

A string that passes over a pulley has a 0.331g mass attached to one end and a 0.625g mass attached to the other end. The pulley, which is a disk of radius 9.50cm , has friction in its axle.
What is the magnitude of the frictional torque that must be exerted by the axle if the system is to be in static equilibrium?

Answer 1

Difference in mass, Δm
= 0.625-0.331 g
= 0.294/1000 kg
= 0.000294 kg

Radius, r
= 9.5 cm
= 0.095 m

Torque required
=Δm * r Nm

Answer 2

F=mv^2/r v=u^2+2as