Asked by bobjahng2
The reaction,
cyclopropane propene (isomerization),
was observed to have rate constants k = 0.000213 s-1 at 477 °C and k = 0.0328 s-1 at 577 °C. What is the value of Ea expressed in kJ mol-1? Round your answer to 3 significant figures.
cyclopropane propene (isomerization),
was observed to have rate constants k = 0.000213 s-1 at 477 °C and k = 0.0328 s-1 at 577 °C. What is the value of Ea expressed in kJ mol-1? Round your answer to 3 significant figures.
Answers
Answered by
DrBob222
Plug your numbers into the Arrhenius equation and solve for Ea.
Answered by
bobjahng2
i don't get the right answer. Plus arent we missing A?
Answered by
DrBob222
I use ln(k2/k1) = (Ea/R)(1/T1 - 1/T2)
Don't forget that Ea is in Joules, R = 8.314 and T must be in Kelvin.
Don't forget that Ea is in Joules, R = 8.314 and T must be in Kelvin.
Answered by
Amelia
Please for the love of god explain how i do the last bit of this equation on the calculator
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