Question

Cyclopropane is converted to propene in a first-order process. The rate constant is 5.4 × 10-2 hr-1. If
the initial concentration of cyclopropane is 0.150 M, what will its concentration be after 22.0 hours?

Answer 1

k=5.4x10^-2
t=22.0 hours
initial=0.150 M
final=?


ln(x/0.150) = - (5.4x10^-2)(22.0)
x= 0.127

Answer 2

.0457