you have 100 mL of a saturated solution of Pb(NO3)2 at 0 degrees celsius. If the solution is evaporated to dryness how many grams of Pb(NO3)2 do you expect to remain in the crucible?
Im not sure how to do this because i don't have a number to work with besides the 100ml. Help please
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I found the solubility at a number of temperatures but not at zero. You might have better luck on google than I. Type in solubility of lead nitrate.
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