[w^1 / w^-3]^-4

Question

= w3

? is this correct?

Answer 1

Use the laws of exponents:
x^a*x^b = x^a+b
x^a/x^b = x^a-b
(x^a)^b = x^ab
x^-a = 1/x^a
x^1/a = ath root of x

[w^1 / w^-3]^-4
= [w^1 * w³]^-4
= (w¹⁺³)^-4
= w⁴^-4
= 1/(w⁴)^4
= 1/w^4*4
= 1/w¹⁶
or
= w^-16