Asked by Joshua



[w^1 / w^-3]^-4

= w3

? is this correct?
Answered by MathMate
Use the laws of exponents:
x<sup>a</sup>*x<sup>b</sup> = x<sup>a+b</sup>
x<sup>a</sup>/x<sup>b</sup> = x<sup>a-b</sup>
(x<sup>a</sup>)<sup>b</sup> = x<sup>ab</sup>
x<sup>-a</sup> = 1/x<sup>a</sup>
x<sup>1/a</sup> = ath root of x

[w^1 / w^-3]^-4
= [w^1 * w³]^-4
= (w<sup>1+3</sup>)^-4
= w<sup>4</sup>^-4
= 1/(w<sup>4</sup>)^4
= 1/w<sup>4*4</sup>
= 1/w<sup>16</sup>
or
= w<sup>-16</sup>
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