Consider the following reaction at equilibrium:

2NH3 (g)<-> N2 (g) + 3H2 (g) ΔH° = +92.4 kJ
Le Cha
^
telier's principle predicts that increasing the temperature will shift the reaction to the.
a) stays same b)leftc)none d)right

i was told right by some people and left by some people.???

1 answer

You received different answers because you didn't make it clear which way the reaction is going to obtain delta H of +92.4 kJ and/or some of the responders didn't note that it is delta Ho.
delta Ho is the heat of FORMATION which means
1/2 N2 + 3/2 H2 ==> NH3 delta Ho = delta Hrxn = 46.2 kJ/mol
So for your reaction, we have
N2 + 3H2 ==> 2NH3 for which delta H rxn = +92.4 kJ.
That makes the equation I've written an endothermic reaction and adding heat will shift it to the right (to the NH3 side)
Similar Questions
  1. I am given the following reaction:2NH3(g) -------> N2(g) + 3H2(g) My question is: 6.4 mols of ammonia gas has been put into a
    1. answers icon 0 answers
  2. I am given the following reaction:2NH3(g) -------> N2(g) + 3H2(g) My question is: 6.4 mols of ammonia gas has been put into a
    1. answers icon 2 answers
    1. answers icon 1 answer
  3. Use the reaction to answer the question.N2(g) + 3H2(g) ⇄ 2NH3(g) + energy When this reaction has reached equilibrium, how will
    1. answers icon 4 answers
more similar questions