Asked by richy
Consider the following reaction at equilibrium:
2NH3 (g)<-> N2 (g) + 3H2 (g) ΔH° = +92.4 kJ
Le Cha
^
telier's principle predicts that increasing the temperature will shift the reaction to the.
a) stays same b)leftc)none d)right
i was told right by some people and left by some people.???
2NH3 (g)<-> N2 (g) + 3H2 (g) ΔH° = +92.4 kJ
Le Cha
^
telier's principle predicts that increasing the temperature will shift the reaction to the.
a) stays same b)leftc)none d)right
i was told right by some people and left by some people.???
Answers
Answered by
DrBob222
You received different answers because you didn't make it clear which way the reaction is going to obtain delta H of +92.4 kJ and/or some of the responders didn't note that it is delta Ho.
delta Ho is the heat of FORMATION which means
1/2 N2 + 3/2 H2 ==> NH3 delta Ho = delta Hrxn = 46.2 kJ/mol
So for your reaction, we have
N2 + 3H2 ==> 2NH3 for which delta H rxn = +92.4 kJ.
That makes the equation I've written an endothermic reaction and adding heat will shift it to the right (to the NH3 side)
delta Ho is the heat of FORMATION which means
1/2 N2 + 3/2 H2 ==> NH3 delta Ho = delta Hrxn = 46.2 kJ/mol
So for your reaction, we have
N2 + 3H2 ==> 2NH3 for which delta H rxn = +92.4 kJ.
That makes the equation I've written an endothermic reaction and adding heat will shift it to the right (to the NH3 side)
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