Asked by joe
For the reaction 2NH3(g) 3H2(g) N2(g) at 472oC equilibrium is established when [H2] =0.0200M, [N2] = 0.0100M and [NH3] = 5.37x10^_8 M. What is the equilibrium constant for the reverse reaction?
Answers
Answered by
DrBob222
Write the equilibrium constant expression and substitute the numbers from the problem. Then solve for Kc
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