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CO (g) + Cl2 (g) ↔ COCl2 (g In one experiment, 0.93 bar of CO was combined with 1.01 bars of Cl¬2 in a reaction vessel at 700K....Asked by jason
CO (g) + Cl2 (g) ↔ COCl2 (g In one experiment, 0.93 bar of CO was combined with 1.01 bars of Cl¬2 in a reaction vessel at 700K. After the system reached equilibrium, the total pressure was 1.24 bars. Calculate Kp0 for the system.
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Answered by
DrBob222
Try this.
PCO + PCl2 + PCOCl2 = 1.24
1 mole CO reacts with 1 mole Cl2 to produce 1 mole COCl2 so
3x = 1.24
solve for x to find partial pressure of COCl2. Then PCO = 0.93-x; PCl2 = 1.01-x, substitute those into the Kp expression and solve for Kp.
PCO + PCl2 + PCOCl2 = 1.24
1 mole CO reacts with 1 mole Cl2 to produce 1 mole COCl2 so
3x = 1.24
solve for x to find partial pressure of COCl2. Then PCO = 0.93-x; PCl2 = 1.01-x, substitute those into the Kp expression and solve for Kp.
Answered by
Sally
Are you in chem 109?
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