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Original Question
solve the equation by completing the square: x^2-9x-2=0Asked by Lily
solve the equation by completing the square
3x^2-12x+1=0
3x^2-12x+1=0
Answers
Answered by
bobpursley
x^2-4x+1/3=0
x^2-4x = -1/3
x^2-4x+4=4-1/3
(x-2)^2=(sqrt (3 2/3))^2
x-2=+- sqrt (3 2/3)
x^2-4x = -1/3
x^2-4x+4=4-1/3
(x-2)^2=(sqrt (3 2/3))^2
x-2=+- sqrt (3 2/3)
Answered by
Darren
or...
3x^2 -12x+ 36 = 35
(x-6)^2 = 35
x-6 = square root of 35
x= 6+ or 6- the square root of 35
3x^2 -12x+ 36 = 35
(x-6)^2 = 35
x-6 = square root of 35
x= 6+ or 6- the square root of 35
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