Question

Sevnety-eight players entered a single elimination tennis tournament.How many matches were played to determine the overall champ?

please help me...and if u get the answer can you explain how you got it with a rule or a pattern

Answer 1

I did this a few minutes ago

Answer 2

math - Damon, Tuesday, November 16, 2010 at 7:47pm

2 players in final
4 in semi final
8 in quarter final etc
16
32
64 note powers of two
there can be only 64 of the 78 in this round so there must be one beginning round with a lot of byes to winnow 78 down to 64.
78-64 = 14 players must be eliminated
so there must be 7 matches in this initial round
7 + 32 + 16 + 8 + 4 + 2 + 1

Answer 3

but why would u do 7+32+16+8+4+2+1...what does that have to do with anything???..and i asked another peron and they gave me this answer:

In the first round, with 78 players, there would be 39 matches. However, with the 39 winners, there would be 18 matches and one bye. With the 9 winners and one bye, there would be 5 matches. With the five winners, there would be two more matches and one bye. I would assume the bye then would play one of the winners, and the winner of that match would play the other winner for the championship. How many matches is that?

i don't know..but this is so confusing....can u please show me or describe how you got the answer....how did you get the 2 players in final
4 in semi final...ect...

Answer 4

please help me