Asked by Kristi

A total of 129 players entered a single-elimination hand ball tournament. In the first round of play, the top-seeded player received a bye and the remaining 128 players played in 64 matches. Thus, 65 players entered the second round of play. How many matches must be played to determine the tournament champion?

Answers

Answered by bobpursley
first round:
128
second round
64
third round=
32
fourth round
16
fifth
8
sixth
4
seventh
2
eigth
1+ player getting the bye.
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