Asked by Emily

How do you get the general term for a sequence that has increasing common differences? For example: 1,2,4,7,11

Answers

Answered by Reiny
notice that the differences are 1,2,3,4,...
but the differences of those differences are 1,1,1,...

Since we have constants in the second set of differences our sequence can be expressed as a 2nd degree expression
(had the third set of differences been constant, it would have been a cubic expression, etc)

so let the sequence be written as
t(n) = an^2 + bn + c

if n=1 ---> a + b + c = 1
if n=2 ---> 4a + 2b + c = 2
if n=3 ---> 9a + 3b + c = 4

subtract the first two ---> 3a + b = 1
subtract the last two ---> 5a + b = 2

now subtract those
2a = 1
a = 1/2
back in 3a+b=1
3/2 + b = 1
b = -1/2
back in a+b+c=1
1/2 - 1/2 + c = 1
c=1

<b>so t(n) = (1/2)n^2 - (1/2)n + 1
= (1/2)(n^2 - n + 2)</b>

checking for t(5)
= (1/2)(25-5+2)
=(1/2)(22) = 11
Answered by Emily
why do you let n=1, 2 and 3?

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