Asked by Lizzy
how would you solve this equation? please help!
(x/2)LOG 7 = LOG 5 - xLOG 5
(x/2)LOG 7 = LOG 5 - xLOG 5
Answers
Answered by
Reiny
multiply by 2
xlog7 = 2log5 - 2xlog5
xlog7 + 2xlog5) = 2log5
x(log7 - 2log5) = 2log5
x = 2log5/(log7-2log5)
= ... you do the button-pushing
(I had appr. -2.529)
xlog7 = 2log5 - 2xlog5
xlog7 + 2xlog5) = 2log5
x(log7 - 2log5) = 2log5
x = 2log5/(log7-2log5)
= ... you do the button-pushing
(I had appr. -2.529)
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