Question
Hi,
3D GEOMETRY
(P) a surface. (AB), (AC), (BC) lines that intercept the surface in three points M1, M2, M3.
We have
Vector(M1A) = k1 * Vector(M1B)
Vector(M1C) = k2 * Vector(M1A)
Vector(M1B) = k3 * Vector(M1C)
Show that k1*k2*k3=1.
Thanks!
3D GEOMETRY
(P) a surface. (AB), (AC), (BC) lines that intercept the surface in three points M1, M2, M3.
We have
Vector(M1A) = k1 * Vector(M1B)
Vector(M1C) = k2 * Vector(M1A)
Vector(M1B) = k3 * Vector(M1C)
Show that k1*k2*k3=1.
Thanks!
Answers
bobpursley
Multipy the left sides together.
VMA*VMB*VMC
Now the right sides
k1*k2*k3*VM1*VM2*VM3
divide both sides by the common factor.
VMA*VMB*VMC
Now the right sides
k1*k2*k3*VM1*VM2*VM3
divide both sides by the common factor.