Asked by Pinky
Geometry help
Answers
Answered by
TX2lover99
bro i just posted the answers for u pinky
Answered by
TX2lover99
@pinky try these
Lesson 7 Circle Unit Test.
Here you go:
1- 19.6
2- 78
3-243
4-53.0
5-53.5
6-73
7-31
8-54
9-15.8
10-35.9
11-C (circle on the graph on the left hand side)
12-28
13-11.6
14-56
15-26616-x=15 & triangle is isoscles
17- Paraphrase please!- The center of the circle described by the equation is (-6,-4), so that is the position of the source. The radius of the circle is the square root of 36, which is 6. This means that the range of the radio signal extends out 6 units from the source in all directions. Therefore, any point on the circle with center (-6,-4) and radius 6 is within range of the radio signal.
18- A.((-10+4)/2,(-2+9)/2)
(-3,3.5)
B. sqrt ( ( -10-(-3))^2+(-2-3.5)^2)
sqrt (49+31.25)
sqrt(80.25)
C. (x+3)^2+(y-3.5)^2=80.25
Lesson 7 Circle Unit Test.
Here you go:
1- 19.6
2- 78
3-243
4-53.0
5-53.5
6-73
7-31
8-54
9-15.8
10-35.9
11-C (circle on the graph on the left hand side)
12-28
13-11.6
14-56
15-26616-x=15 & triangle is isoscles
17- Paraphrase please!- The center of the circle described by the equation is (-6,-4), so that is the position of the source. The radius of the circle is the square root of 36, which is 6. This means that the range of the radio signal extends out 6 units from the source in all directions. Therefore, any point on the circle with center (-6,-4) and radius 6 is within range of the radio signal.
18- A.((-10+4)/2,(-2+9)/2)
(-3,3.5)
B. sqrt ( ( -10-(-3))^2+(-2-3.5)^2)
sqrt (49+31.25)
sqrt(80.25)
C. (x+3)^2+(y-3.5)^2=80.25
Answered by
Bot
Sure, what do you need help with in geometry?
Answered by
Bot
I'm sorry, as an AI language model, I don't have the ability to see your previous posts. Can you please repost your questions or requests for geometry help so I can assist you?
Answered by
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