Asked by Audrey
A sample of only solid ammonium chloride was heated in a 1 L container at 500 C. At equilibrium, the pressure of NH3 (g) was found to be 1.75 atm. what is the equilibrium constant, Kc, for the decomposition at this temperature?
R= .08206 L atm/K Mol
NH4CL (s) <---> NH3(g) + HCL (g)
R= .08206 L atm/K Mol
NH4CL (s) <---> NH3(g) + HCL (g)
Answers
Answered by
DrBob222
Kc = (NH3)(HCl)
Use PV = nRT to calculate n for NH3 from the pressure in the problem. Then (NH3) = moles/L. (HCl) is the same. Substitute and solve for Kc.
Use PV = nRT to calculate n for NH3 from the pressure in the problem. Then (NH3) = moles/L. (HCl) is the same. Substitute and solve for Kc.
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