A sample of only solid ammonium chloride was heated in a 1 L container at 500 C. At equilibrium, the pressure of NH3 (g) was found to be 1.75 atm. what is the equilibrium constant, Kc, for the decomposition at this temperature?

Question

R= .08206 L atm/K Mol

NH4CL (s) <---> NH3(g) + HCL (g)

Answer 1

Kc = (NH3)(HCl)

Use PV = nRT to calculate n for NH3 from the pressure in the problem. Then (NH3) = moles/L. (HCl) is the same. Substitute and solve for Kc.