Question

1.00 mol of A and 2.00 mol of B are placed in a 5 Liter container. after equilibrium has been established, .50 mol of D is present in the container. What is the equilibrium constant, Kc?

A + 2B <---> 2C + D

Answer 1

Kc = (C)^2(D)/(A)(B)^2

Initial:
A = 1.00/5.00 = ??
B = 2.00/5.00 = ??
C = 0
D = 0

equilibrium:
D = 0.50/5.00 from the problem
C = 2*D
A = initial-D
B = initial-2D

Substitute into Kc and solve.