Question
Maria throws an apple vertically upward from a height of 1.2 m with an initial velocity of +2.7 m/s.
Will the apple reach a friend in a tree house 4.8 m above the ground?
the tree house
2. No, the apple will reach 1.40733 m below
the tree house
3. No, the apple will reach 3.22844 m below
the tree house
4. No, the apple will reach 1.27691 m below
the tree house
5. Yes, the apple will reach 3.22844 m above
the tree house
6. Yes, the apple will reach 1.40733 m above
the tree house
Will the apple reach a friend in a tree house 4.8 m above the ground?
the tree house
2. No, the apple will reach 1.40733 m below
the tree house
3. No, the apple will reach 3.22844 m below
the tree house
4. No, the apple will reach 1.27691 m below
the tree house
5. Yes, the apple will reach 3.22844 m above
the tree house
6. Yes, the apple will reach 1.40733 m above
the tree house
Answers
bobpursley
vi^2=2g*height solve for max height.
v = vi - 9.8 t
v = 0 at max height
so
t = 2.7/9.8 time to top = .276
h = 1.2 + 2.7 t -4.9 t^2
=1.57
4.8 - 1.57 = 3.22 below the house
v = 0 at max height
so
t = 2.7/9.8 time to top = .276
h = 1.2 + 2.7 t -4.9 t^2
=1.57
4.8 - 1.57 = 3.22 below the house
how long will it be in the air before it hits the ground?
Vf^2 = Vo^2 + 2gd = 0,
(2.7)^2 + 2(-9.8)d = 0,
7.29 - 19.6d = 0,
-19.6d = - 7.29,
d = -7.29 / -19.6 = 0.372 m. upward.
d(tot.) = 1.2 + 0.372 = 1.57 m.
4.8 - 1.57 = 3.228 m below the house.
(2.7)^2 + 2(-9.8)d = 0,
7.29 - 19.6d = 0,
-19.6d = - 7.29,
d = -7.29 / -19.6 = 0.372 m. upward.
d(tot.) = 1.2 + 0.372 = 1.57 m.
4.8 - 1.57 = 3.228 m below the house.
Related Questions
Alright in my class we are learning about free fall and crap.
I've wasted tons of time on thins o...
Maria throws an apple vertically upward from a height of 1.3m unit an initial velocity of velocity o...
A joggler throws an apple vertically upward just enough to reach the ceiling exactly 4 meters from t...