Asked by Vanessa
A child throws a rock vertically at 15.0 m/s. It lands on his roof 3.0m above the ground. How long was the rock in the air and what was its speed just before it hit the roof?
Answers
Answered by
bobpursley
hf=hi+vi*t-4.9t^2
3=0+15t -4.9t^2
put this in standard quadratic form, and solve for t.
t=(-b+-sqrt(b^2-4ac))/2a
speed: either vf=vi-g t or
vf^2=vi^2+2g*3.0
3=0+15t -4.9t^2
put this in standard quadratic form, and solve for t.
t=(-b+-sqrt(b^2-4ac))/2a
speed: either vf=vi-g t or
vf^2=vi^2+2g*3.0
Answered by
bobpursley
where g=-9.8m/s^2 on that last formula.
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