To find the molarity of the iodine solution and titer, we need to use the equation:
Molarity (M) = (moles of solute) / (volume of solution in liters) ----(1)
Titer = volume of iodine solution used in the titration
First, we need to find the moles of ascorbic acid (solute).
A. Calculation of moles of ascorbic acid:
Given:
Mass of ascorbic acid (solute) = 0.1000 g (grams)
Using the molecular formula of ascorbic acid (C6H8O6), we can find the molar mass:
C = 6 * 12.01 g/mol
H = 8 * 1.01 g/mol
O = 6 * 16.00 g/mol
Molar mass of ascorbic acid = (6 * 12.01) + (8 * 1.01) + (6 * 16.00) g/mol
Now, we can calculate the moles of ascorbic acid using the given mass, molar mass, and the equation:
moles of ascorbic acid = (mass of ascorbic acid) / (molar mass of ascorbic acid)
moles of ascorbic acid = 0.1000 g / (C6H8O6 molar mass)
B. Calculation of Molarity of Iodine Solution:
Using the stoichiometry of the reaction, we know that 1 mole of ascorbic acid reacts with 1 mole of iodine (I2).
Therefore, moles of iodine (I2) = moles of ascorbic acid
Now, we need to find the volume of the iodine solution in liters.
Given:
Volume of iodine solution used = 25.32 mL
Volume of iodine solution used (in L) = 25.32 mL / 1000 mL/L
Now, we can calculate the molarity of the iodine solution using the moles of iodine and the volume:
Molarity of iodine solution (I2) = (moles of iodine) / (volume of iodine solution used in L)
B. Calculation of Titer of Iodine Solution:
Titer = volume of iodine solution used in the titration
Given:
Volume of iodine solution used = 25.32 mL
Therefore, the titer of the iodine solution is 25.32 mL.
Please note that the titer is a measure of the concentration of the iodine solution. It represents the volume of the solution required to react completely with a known amount of the substance being titrated (ascorbic acid in this case).