Break the coefficeint of the x^2 term and the constant both into prime number factors (a*b) and (c*d), and then try various combinations of (ax+c)(bx+d) until you find one that works.
For 8x^2-10x+3, choose 4 and 2 for the factors of 8 and 3 and 1 for the factors of 3.
(4x - 3)(2x - 1) works!
The pair of minus signs before 3 and 1 is needed to make the 3 positive and -10 negative in the final product
Factor each expression. Please show me how to do it. Thanx
8x^2-10x+3
15X^2-x-2
8X^2-18X-5
2x^2-5x-88
3x^2+43x-30
3x^2+7x-2
10^2-89x+156
4x^2+11x+13
3x^2-42x+147
5x^2-20x+20
1 answer
1 answer