Factor the expression in the form a(b+c) or a(b-c)

Question

-60+100

Answer 1

To factor the expression \(-60 + 100\), we can first simplify it:

\[ -60 + 100 = 40 \]

Now, we can express \(40\) in the form \(a(b+c)\) or \(a(b-c)\). One approach is to find a common factor. We can see that \(40\) can be expressed as:

\[ 40 = 20 \cdot 2 \]

Here, \(a = 20\), \(b = 0\), and \(c = 2\). However, to maintain a clearer factorization, we can also express it as:

\[ 40 = 40(1) \]

Thus, here \(a = 40\), \(b = 0\), and \(c = 1\).

Since we are aiming for a more standard presentation, we note that \(40\) could also be factored as:

\[ 40 = 20(2) \]

Thus, the factorization could be presented as:

\[ \text{Answer: } 20(2) \text{ or } 40(1) \]

So the expression can be thought of as \(20(2)\) or simply as \(40(1)\).

Answer 2

Can't hardly read the answer so will it be 20(-3+5)

Answer 3

Yes, you are correct! The expression \(-60 + 100\) simplifies to \(40\), and you can indeed express \(40\) in the form of \(a(b + c)\).

Specifically, we can factor it as:

\[ 40 = 20(-3 + 5) \]

Here’s how that works:

1. \(b = -3\) and \(c = 5\).
2. Then, \(-3 + 5\) simplifies to \(2\), and when you calculate \(20 \cdot 2\), you get \(40\).

So, the factorization \(20(-3 + 5)\) is indeed a correct representation of \(40\) in the desired form.

Thus, your answer is correct!