Asked by Hello
Factor the expression in the form a(b+c) or a(b-c)
-60+100
-60+100
Answers
Answered by
Hello
Can't hardly read the answer so will it be 20(-3+5)
Answered by
GPT-4o mini
To factor the expression \(-60 + 100\), we can first simplify it:
\[
-60 + 100 = 40
\]
Now, we can express \(40\) in the form \(a(b+c)\) or \(a(b-c)\). One approach is to find a common factor. We can see that \(40\) can be expressed as:
\[
40 = 20 \cdot 2
\]
Here, \(a = 20\), \(b = 0\), and \(c = 2\). However, to maintain a clearer factorization, we can also express it as:
\[
40 = 40(1)
\]
Thus, here \(a = 40\), \(b = 0\), and \(c = 1\).
Since we are aiming for a more standard presentation, we note that \(40\) could also be factored as:
\[
40 = 20(2)
\]
Thus, the factorization could be presented as:
\[
\text{Answer: } 20(2) \text{ or } 40(1)
\]
So the expression can be thought of as \(20(2)\) or simply as \(40(1)\).
\[
-60 + 100 = 40
\]
Now, we can express \(40\) in the form \(a(b+c)\) or \(a(b-c)\). One approach is to find a common factor. We can see that \(40\) can be expressed as:
\[
40 = 20 \cdot 2
\]
Here, \(a = 20\), \(b = 0\), and \(c = 2\). However, to maintain a clearer factorization, we can also express it as:
\[
40 = 40(1)
\]
Thus, here \(a = 40\), \(b = 0\), and \(c = 1\).
Since we are aiming for a more standard presentation, we note that \(40\) could also be factored as:
\[
40 = 20(2)
\]
Thus, the factorization could be presented as:
\[
\text{Answer: } 20(2) \text{ or } 40(1)
\]
So the expression can be thought of as \(20(2)\) or simply as \(40(1)\).
Answered by
GPT-4o mini
Yes, you are correct! The expression \(-60 + 100\) simplifies to \(40\), and you can indeed express \(40\) in the form of \(a(b + c)\).
Specifically, we can factor it as:
\[
40 = 20(-3 + 5)
\]
Here’s how that works:
1. \(b = -3\) and \(c = 5\).
2. Then, \(-3 + 5\) simplifies to \(2\), and when you calculate \(20 \cdot 2\), you get \(40\).
So, the factorization \(20(-3 + 5)\) is indeed a correct representation of \(40\) in the desired form.
Thus, your answer is correct!
Specifically, we can factor it as:
\[
40 = 20(-3 + 5)
\]
Here’s how that works:
1. \(b = -3\) and \(c = 5\).
2. Then, \(-3 + 5\) simplifies to \(2\), and when you calculate \(20 \cdot 2\), you get \(40\).
So, the factorization \(20(-3 + 5)\) is indeed a correct representation of \(40\) in the desired form.
Thus, your answer is correct!
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