What mass of benzene(C6H6, molar mass=78.11g/mol) is required to produce 1500 kJ of heat according to the following reaction?

2C6H6(l)+15O2(g) -> 12CO2(g) +6H2O(g)
delta H= -6278

I must have tried this so many times. Can you please show me how this is done. Thanks

3 answers

78.11 g = mass 1 mole benzene
2*78.11 g = mass 2 moles benzene.

2*78.11 will produce 6278 (I guess that's kJ?), then
2*78.11 x (1500 kJ/6278 kJ) = ??

Yes sorry that was kJ

and thank you very much.