Asked by Sarah
Benzene (C6H6) has a normal freezing point of 5.50oC and a density of 0.88 g/mL. When 1.28 g of naphthalene (C10H8) is dissolved in 125 mL of benzene, the freezing point of the solution is 5.03oC. Determine the molal freezing point constant for this solvent.
Answers
Answered by
DrBob222
mass = density*volume
mass benzene = 0.88 g/mL x 125 mL = ?
delta T = Kf*m
You know delta T.
m = mols/kg solvent;
mols naph = 1.28/molar mass naphthalene
kg solvent = ? g benzene/1000
Solve for Kf
mass benzene = 0.88 g/mL x 125 mL = ?
delta T = Kf*m
You know delta T.
m = mols/kg solvent;
mols naph = 1.28/molar mass naphthalene
kg solvent = ? g benzene/1000
Solve for Kf
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