Asked by Linda
A 23 g bullet traveling 220 m/s penetrates a 4.2 kg block of wood and emerges cleanly at 140 m/s.
If the block is stationary on a frictionless surface when hit, how fast does it move after the bullet emerges?
If the block is stationary on a frictionless surface when hit, how fast does it move after the bullet emerges?
Answers
Answered by
bobpursley
conservation of momentum:
M*0+23*220=M*Vf+23*140
M = 4200 grams solve for Vf
M*0+23*220=M*Vf+23*140
M = 4200 grams solve for Vf
Answered by
Anonymous
230
Answered by
Shane
140 m/s
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