Asked by Linda

A 23 g bullet traveling 220 m/s penetrates a 4.2 kg block of wood and emerges cleanly at 140 m/s.

If the block is stationary on a frictionless surface when hit, how fast does it move after the bullet emerges?

Answers

Answered by bobpursley
conservation of momentum:

M*0+23*220=M*Vf+23*140
M = 4200 grams solve for Vf
Answered by Anonymous
230
Answered by Shane
140 m/s
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