Asked by Kathleen

A 500 g steel block
rotates on a steel table while attached to a 2.0-m-long massless rod. Compressed air fed through the rod is ejected from a Inozzle on the back of the block, exerting a thrust force of 3.5 N. The nozzle is 70^\circ from the radial line, as shown in the figure . The block starts from rest.
a)What is the block's angular velocity after 10 rev?
b)What is the tension in the rod after 10 rev?

Answers

Answered by bobpursley
the moment of inertia is mr^2 .

Torque=thrust*radiusrotation=I*angacceleration

solve for angular acceleration.
Then, wf^2=2*a*displacementinradians

tension= m*w^2*r
Answered by Anonymous
Tough one, cutie.
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