Asked by mack
A steel block is resting on a Flat plank 6m long ,and how high can one end of a plank be lifted For the block to start to move,if the coeficient of friction is 0.3
Answers
Answered by
Don
I feel like the weight of the steel block has to be given in order to solve this problem…
Answered by
Henry
Fp = mg*sin A = Force parallel to the
incline.
Fn = mg*Cos A = Normal = Force perpendicular to the incline.
Fs = u*Fn = Force of static friction.
Fp-Fs = 0
Fp = Fs
mg*sin A = u*mg*Cos A
Divide both sides by mg*Cos A:
sin A/Cos A = u = 0.3
sin A/Cos A = Tan A
Tan A = 0.30
A = 16.7o
h = L*sin16.7 = 6*sin16.7 = 1.72 m.
incline.
Fn = mg*Cos A = Normal = Force perpendicular to the incline.
Fs = u*Fn = Force of static friction.
Fp-Fs = 0
Fp = Fs
mg*sin A = u*mg*Cos A
Divide both sides by mg*Cos A:
sin A/Cos A = u = 0.3
sin A/Cos A = Tan A
Tan A = 0.30
A = 16.7o
h = L*sin16.7 = 6*sin16.7 = 1.72 m.
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