Question
One multicellular organism is a cube. Each of its sides is 3cm long. Each of its cells is 1cm to the third power.How many cells does it have? If each side doubles in length,how many cells will it then have?
Answers
bobpursley
number cells=total volume/cellvolume=3^3/1^3=27
if each side doubles, volume is now 2^3*27
if each side doubles, volume is now 2^3*27
ÀÌÁö¿¹
The area of a cube can be found by AxBxC. Your cube is 27cm cubed. 27 of the little cells will fit in the cube.
Deez Nuts
Deez Nuts is your answer
±è¿¬Àç
Answer to first Question: 27 cells
Answer to Second Question: 126 cells
b/c 1st : 3*3*3=27
b/c 2nd : 2*3*2*3*2*3= 6*6*6= 126
Answer to Second Question: 126 cells
b/c 1st : 3*3*3=27
b/c 2nd : 2*3*2*3*2*3= 6*6*6= 126
±è¿¬Àç
Sorry... It 216 for the second question....... ¤Ð¤Ð
Lol;)
1= 27 (3*3*3)
2= 216 (3*2*3*2*3*2)
2= 216 (3*2*3*2*3*2)