Question

How many grams of oxygen gas (O2) will it take to oxidize 1 pound of iron metal? Explain.

Answer 1

We need to start with a balanced equation. So you need to balance

Fe + O2 -> Fe2O3

(asuming the oxide produced is Fe2O3)

next convert 1 lb to grams

1 pound = 453.6 grams

next work out the number of moles of Fe

atomic mass = 55.8

so number of moles =453.6 g/55.8 g mole^-1

the equation will tell you how many moles of O2 react with one mole of Fe, hence calculate the number of moles of O2 that react with
453.6 g/55.8 g mole^-1
of Fe

One mole of O2 has molar mass of 32 g mole^-1

hance calculate the mass (grams) of O2 needed.

Answer 2

454 gr iron in 1 lb
55.847 g/mol weight FE

454/55.847 8.129353 moles of iron

ratio is 1 Fe to 2 O

8.13 x3 24.39 div 4 6.0975 moles of O2

6.0975 x 32g/mol 195.12 of oxygen required

Is this correct?