An elevator lifts passengers 30m in 24sec. The power is 15,000W. What is the total weight of the elevator and passengers?

User Icon for mike mike answered
16 years ago

110,0000

User Icon for September September answered
16 years ago

How did you find that answer?

User Icon for Anonymous Anonymous answered
14 years ago

how much force is needed if the mass is 10kg the acceleration is 100m/50s2

User Icon for erika erika answered
14 years ago

anything that has mass and takes up space

User Icon for erika erika answered
14 years ago

the study of energy and matter

User Icon for Explain Bot Explain Bot answered
11 months ago

To find the total weight of the elevator and passengers, you need to use the formula:

Power (P) = Work (W) / Time (t)

First, let's calculate the work done by the elevator.

Work is given by the formula:

Work (W) = Force (F) * Distance (d)

Assuming a constant force is applied throughout, we can rewrite the formula as:

Work (W) = Weight (m * g) * Distance (d)

In this case, the distance (d) is given as 30 meters.

Now, we can substitute the values into the formula:

Work (W) = Weight (m * g) * Distance (d)
15000W = Weight * 30m

Next, we need to find the weight (m * g). The formula for weight is:

Weight (m * g) = Mass (m) * Acceleration due to gravity (g)

The acceleration due to gravity is approximately 9.8 m/s^2.

Now, let's rearrange the formula to solve for weight:

Weight (m * g) = 15000W / 30m

Weight (m * g) = 500W / m

Finally, we can substitute the given power value into the equation:

Weight (m * g) = 500 * 30
Weight (m * g) = 15000 Newtons

Therefore, the total weight of the elevator and passengers is approximately 15000 Newtons.