An elevator motor provides 32kW of power while it lifts the elevator 24 m at a constant speed. If the elevator’s mass is 2200 kg, including the passengers, how long does the motion take?
2 answers
m * g * h / t = 32 kW ... m * g * h / 32 kW = t ... seconds
Takes time T
change in potential energy = m g h = 2200 * 9.81 * 24 = 518,000 Joules
energy = power * time
518,000 = 32,000 Joules/second * T
T = 16.2 seconds
change in potential energy = m g h = 2200 * 9.81 * 24 = 518,000 Joules
energy = power * time
518,000 = 32,000 Joules/second * T
T = 16.2 seconds
2 answers