3x^2 + 5y^4 dy/dx = 0
dy/dx = -3x^2/(5y^4)
How do you find dy/dx by implicit differentiation?
x^3 + y^5 = 1
Damon answer isn't right and I have no idea what he did. Somebody please help.
1 answer
x^3 + y^5 = 1
Damon answer isn't right and I have no idea what he did. Somebody please help.
1 answer
1 answer
1 answer
1 answer
2 answers