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How do you find dy/dx by implicit differentiation?
x^3 + y^5 = 1
14 years ago

Answers

Damon
3 x^2 dx + 5 y^4 dy = 0

dy/dx = -3 x^2/5y^4

if needed as function of x only then
y = (1-x^3)^.2
y^4 = (1-x^3)^.8
so
dy/dx = -(3/5)x^2/(1-x^3)^.8
14 years ago

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