Asked by Anonymous
How do you find dy/dx by implicit differentiation?
x^3 + y^5 = 1
x^3 + y^5 = 1
Answers
Answered by
Damon
3 x^2 dx + 5 y^4 dy = 0
dy/dx = -3 x^2/5y^4
if needed as function of x only then
y = (1-x^3)^.2
y^4 = (1-x^3)^.8
so
dy/dx = -(3/5)x^2/(1-x^3)^.8
dy/dx = -3 x^2/5y^4
if needed as function of x only then
y = (1-x^3)^.2
y^4 = (1-x^3)^.8
so
dy/dx = -(3/5)x^2/(1-x^3)^.8
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