Asked by franklin
Given the linear equation y=1/3x-3, find the y-coordinates of the points (-6, ), (-3, ), and (6, )
Answers
Answered by
Henry
Y = X/3 - 3.
Y = -6/3 - 3 = -5, (-6 , -5).
Y = -3/3 - 3 = -4, (-3 , -4).
Y = 6/3 - 3 = -1, (6 , -1).
Y = -6/3 - 3 = -5, (-6 , -5).
Y = -3/3 - 3 = -4, (-3 , -4).
Y = 6/3 - 3 = -1, (6 , -1).
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