Asked by Jay Kay

A rock is thrown from on a cliff with the velocity of 15 m/s at an angle of 30 degrees. it takes the rock 6.30 seconds to hit the ground. how high was the cliff?

Answers

Answered by bobpursley
hfinal=hinitial+Vi*t-4.9t^2

you have hfinal=0, t, Vi=15sin30, solve for hinitial
Answered by Jay Kay
Where does the 4.9 come from though?
Answered by bobpursley
1/2 g= 4.9
Answered by Jay Kay
Oh, is it .5 multiplied by the acceleration of gravity?
Answered by bobpursley
yes.
Answered by Jay Kay
Alright. Thank you so much for your help!
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