Question
A rock is thrown from on a cliff with the velocity of 15 m/s at an angle of 30 degrees. it takes the rock 6.30 seconds to hit the ground. how high was the cliff?
Answers
bobpursley
hfinal=hinitial+Vi*t-4.9t^2
you have hfinal=0, t, Vi=15sin30, solve for hinitial
you have hfinal=0, t, Vi=15sin30, solve for hinitial
Where does the 4.9 come from though?
bobpursley
1/2 g= 4.9
Oh, is it .5 multiplied by the acceleration of gravity?
bobpursley
yes.
Alright. Thank you so much for your help!
Related Questions
A rock is thrown horizontally off of a cliff. It starts with a velocity of 4.2 m/s and the cliff is...
A rock is thrown vertically upward from the edge of a cliff. The rock reaches a maximum height of 20...
A rock is thrown horizontally off of a cliff. It starts with a velocity of 4.2 m/s and the cliff is...