Question

A rock is thrown from on a cliff with the velocity of 15 m/s at an angle of 30 degrees. it takes the rock 6.30 seconds to hit the ground. how high was the cliff?

Answer 1

a = V/T = 15 / 6.3 = 2.38 m/s^2.

d = Vo*t + 0.5at^2,
= 15*6.3 + 0.5*2.38(6.3)^2,
= 94.5 + 47.2 = 141.7 m @ 30 Deg.

h = 141.7sin30 = 70.9 m.