Asked by holly
equal masses of ice at 0 oC, water aat 50 oC and steam at 100 oC are mixed and allowed to reach equilibrium. what will be the final temp of the mixture? and what percentage is the water and what percent will be steam??
Answers
Answered by
SraJMcGin
Please see your next post, whic I saw first.
Sra
Sra
Answered by
bobpursley
The sum of the heats gained will be zero.
Heat gained by steam matter + heat gained by ice matter =0
m*Lv+m*cwater*(Tf-100)+m*Lf+m(Tf-0)=0
you know the two latent heats (vaporization, fusion, specific heat water) and mass divides out. Find Tf
Heat gained by steam matter + heat gained by ice matter =0
m*Lv+m*cwater*(Tf-100)+m*Lf+m(Tf-0)=0
you know the two latent heats (vaporization, fusion, specific heat water) and mass divides out. Find Tf
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