Asked by Rachel

A 455-g chunk of iron is removed from an oven and plunged into 385g water in an insulated container. The temperature of the water increases from 27 degrees celsius to 89 degrees celsius.

If the specific heat of iron is 0.449 J g^-1 degrees Celsius^-1, what must have been the original temperature of the iron?
Answered by DrBob222
heat lost by the iron + heat gained by water = 0.

[massFe x specific heatFe x (Tfinal-Tinitial)] + [mass water x specific heat water x (Tfinal-Tinitial)] = 0
Only one unknown, Tinitial Fe.
Answered by Rachel
How do I figure out the final Fe?
Answered by Josh
How do you find out the final Fe
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